Here’s my version of palindrome for lisp problems 99 no 06 found here

```
(defun last1 (lst)
(car (last lst)))
(defun palin1 (lst)
(if (equal nil lst)
t
(let ((start (first lst)) (finish (last1 lst)))
(if (equal start finish)
(palin1 (rest (butlast lst)))
nil))))
```

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nice

Good job!:) Saved me a lot of nerves, I was going on the same idea but sort of got lost between parentheses :P

an iterative approach

(defun make-palindrome(list)

(if (= (length list) 1)

list

(dotimes (count (length list) list)

(setf list (append list (list (nth (- (length list) (+ count (+ count 1))) list))))

))

)

A solution using mapcar and reduce

(defun is-palindrome (lst)

(reduce #'(lambda (x y) (if (and x y) t nil))

(mapcar #’eql lst (reverse lst))))

Shorter:

(defun palindrome(list)

(equal list (revers list)))